Rationalise the number (root2-root3)/(root2+root3)
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Solution:
(√2-√3)/(√2+√3)
=[(√2-√3)(√2-√3)]/[(√2+√3)(√2-√3)]
=(√2-√3)²/[(√2)²-(√3)²]
=[(√2)²+(√3)²-2*√2*√3]/[2-3]
= (2+3-2√6)/(-1)
= (5-2√6)/(-1)
= 2√6-5
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