Question

Rationalise: the question is written below
$1 \div 3 + \sqrt{2}$
​

Answer 1

To Find :-

• rationalize $\frac{1}{3+√2}$

$\bf\huge\underline{\underline{ Answer :- }}$

• $\bf \: \frac{1}{3 + \sqrt{2} } = \frac{(3 - \sqrt{2}) }{(3 + \sqrt{2}) \times (3 - \sqrt{2} ) }$

• $\bf\implies \: \frac{3 - \sqrt{2} }{ {3}^{2} - ( \sqrt{2} ) {}^{2} }$

• $\bf\implies \: \frac{3 - \sqrt{2} }{9 - 2}$

• $\bf\implies \: \frac{3 - \sqrt{2} }{7}$

Answer 2

1 ÷ 3 + √2 = 1 ÷ 4.14

= 1 ÷ 4.14 = 0.24

Please mark me as Brainliest