Question

Rationalise the Second question

Answer 1

$\large \frac{2 \sqrt{3} - 3 \sqrt{2} }{2 \sqrt{6} + 5 } \\ \\ = \frac{2 \sqrt{3} - 3 \sqrt{2} }{2 \sqrt{6} + 5} \times \frac{2 \sqrt{6} - 5 }{2 \sqrt{6} - 5} \\ \\ = \frac{4 \sqrt{18} - 10 \sqrt{3} - 6 \sqrt{12 } + 15 \sqrt{2} }{24 - 25} \\ \\ = \frac{12 \sqrt{2} - 10 \sqrt{3} - 12 \sqrt{3} + 15 \sqrt{2} }{ - 1} \\ \\ = 22 \sqrt{3} - 27 \sqrt{2}$

Answer 2

Answer:

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