rationalise this plss
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so here your answer is SecA +TanA
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Hey
Here is your answer,
Sol:
√1+sin A / 1-sin A
= √(1+sin A) / (1-sin A ) x √(1+sin A) / (1+sin A )
= √(1+sin A)2 / (1-sin2 A )
= √(1+sin A)2 / cos2 A
= (1+sin A) / cos A
= (1/cos A + sin A/cos A)
= sec A + tan A.
√1+sin A / 1-sin A = sec A + tan A.
Hope it helps you!
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