Question

rationalised denominator by taking conjugate pairs square root 5 minus square root 3 / square rool5 + square root3

Answer 1

(√5-√3)/(√5+√3),

(√5-√3)/(√5+√3) × (√5-√3)/(√5-√3),

then

(√5-√3)²/(√5²-√3²),

(5+3-2×√5×√3)/(5-3),

(8-2×√15)/2,

then

(4-√15)