Question

rationalised the denominator of of 4 by cube root 60​

Answer 1

Answer:

Step-by-step explanation:

$\frac{4}{\sqrt[3]{60} }$

when we multiply and divide by $\sqrt[3]{60^{2} }$

we get

$\frac{4}{\sqrt[3]{60} }$ $\frac{\sqrt[3]{60^{2} } }{\sqrt[3]{60^{2} }}$

(4$\sqrt[3]{60^{2} }$) / 60

HENCE THEW DENOMINATOR IS RATIONALISED.

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