Math, asked by Anonymous, 1 year ago

Rationalising factor for 1/(5-√2) iis

Answers

Answered by Anonymous
2
hope it helps.u mate.....
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Answered by BrainlyVirat
7
Here is the answer :)

Rationalize the denominator
1/5-√2

 \tt {\frac{1}{5 - \sqrt{2} }}

 \tt{multiply \: it \: by \: \frac{5 + \sqrt{2} }{5 - \sqrt{2} } }

 \tt{\therefore \frac{1}{5 + \sqrt{2} } \times \frac{5 \: + \sqrt{2} }{5 - \sqrt{2} } }

 \tt{ = \frac{5 + \sqrt{2} }{5 - \sqrt{2} \times 5 - \sqrt{2} } }

 \tt {= \frac{5 + \sqrt{2} }{5 {}^{2} - \sqrt{2} \times \sqrt{2} }}

 \tt{= \frac{5 + \sqrt{2} }{25 - 2} = \frac{5 +\sqrt{2} }{23} }

Thus ,

Final answer

 \bf{\frac{5 +\sqrt{2} }{23}}

#BeBrainly!!
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