Math, asked by gullipalliharikrishn, 5 hours ago

rationalising factor of 2√3-5√2​

Answers

Answered by RISTER
12

Answer:

(2+

3

+

5

)(2+

3

5

)=(2+

3

)

2

−(

5

)

2

=4+3+4

3

−5=7+4

3

−5

=2+4

3

=2(1+2

3

)

Now, conjugate of factor 1+2

3

is 1−2

3

=(1+2

3

)(1−2

3

)=1

2

−(2

3

)

2

=1−4×3=−11

∴(2+

3

+

5

)(2+

3

5

)(1−2

3

)

=2(1+2

3

)(1−2

3

)

=2(1

2

−(2

3

)

2

)=2(1−12)=−22,which is rational

Hence, (2+

3

5

)(1−2

3

) is the simplest rationalising factor of 2+

3

+

5

Answered by anirudhayadav393
0

Concept Introduction: Rationalising is the basic mathematics.

Given:

We have been Given:

2 \sqrt{3}  - 5 \sqrt{2}

To Find:

We have to Find: Rationalising Factor of the given Equation.

Solution:

According to the problem, The Rationalising Factor of

 \sqrt{a}  -  \sqrt{b}  =  \sqrt{a}  +  \sqrt{b}

therefore the Rationalising Factor of the given Equation will be,

2 \sqrt{3}  + 5 \sqrt{2}

Final Answer: The Rationalising Factor of the given Equation is

2 \sqrt{3}  + 5 \sqrt{2}

#SPJ2

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