Question

Rationalising factor of cube root of 36

Answer 1

Answer:

cube root of 36 is 6 so simple

Answer 2

Answer:

$\sqrt[3]{6}$ is the rationalizing factor of $\sqrt[3]{36}$ .

Step-by-step explanation:

Explanation:

Given, cube root of 36.

This can be written as $\sqrt[3]{36}$ = $\sqrt[3]{2 . 2. 3. 3 }$.

The "rationalizing factor" is the expression that is multiplied by an irrational expression to get a rational number.

Step 1:

Therefore, $\sqrt[3]{2 . 2. 3. 3 }$ = $(6^2)^\frac{1}{3}$ =  $(6)^\frac{2}{3}$ .

⇒$(6)^\frac{2}{3}$ × $(6)^\frac{1}{3}$ = 6 which is a rational number.

So, if we multiplied $(6)^\frac{2}{3}$ with $\sqrt[3]{6}$  , then the  number become rational number.

Final answer:

Hence, the rationalizing factor of $\sqrt[3]{36}$ is $\sqrt[3]{6}$ .

#SPJ3