rationalising factor of root 1176
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Break the number into prime factors
1176 = 2×2×2×3×7×7
√1176 = √(2×2×2×3×7×7)
=2×7√6
=14√6
1176 = 2×2×2×3×7×7
√1176 = √(2×2×2×3×7×7)
=2×7√6
=14√6
qais:
someone helping you for that :)
first rationalize the value of x.. you will get root2 - 1
and then just put this value...everything will come on your way :)
Answered by
5
First of all take out the factors of 1176....... 1176 = 2×2×2×3×7×7...... Now group the factors which have occurred twice and keep the rest under root ....... 1176 = 2×7√ 3×2 = 14√6...
Heya plzz mark it as best...
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