Rationalising factor of
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Step-by-step explanation:
Given :-
a+³√b
To find:-
Find the Rationalising factor of the given number ?
Solution:-
Given number = a+³√b
It can be written as ³√(a)³+ ³√b
= (a³)⅓ + b⅓
On multiplying with (a³)⅔-a³b⅓+b⅔ then
=> [(a³)⅓ + b⅓][(a³)⅔-a³b⅓+b⅔]
It is in the form (x+y)(x²-xy+y²)
Where , x = (a³)⅓ and y = b⅓
We know that
x³+y³ = (x+y)(x²-xy+y²)
[(a³)⅓ + b⅓][(a³)⅔-a³b⅓+b⅔]
=> [(a³)⅓]³+(b⅓)³
=> a³ + b
The Rationalising factor = (a³)⅔-a³b⅓+b⅔
=> a-a³b⅓+b⅔
Answer:-
The Rationalising factor of a+³√b is a-a³b⅓+b⅔
Used formulae:-
- x³+y³ = (x+y)(x²-xy+y²)
- The product of two irrational numbers is a rational number then they are called Rationalising factors of to each other.
- The Rationalising factor of a+√b is a-√b.
- An irrational number have so many Rationalising factors
- (a^m)^n = a^(mn)
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