rationalising the denominator 2/√2+3
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yr answer in the attachment
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Here u go ♥️♥️♥️♥️
Steps are as follows:
- 2(√2-3)/(√2+3)(√2-3)
- 2(√2-3)/(√2)^2-(3)^2
- 2√2-6/2-9
- 2√2-6/-7
- Now, taking minus as common.
- 6-2√2/7.
Or,
FROM STEP - 2 YOU WILL GET,
- 2(√2-3)/-7
- -2(√2-3)/7. [AS DENOMINATOR CANNOT BE NEGATIVE]
HOPE it helps u.............✌️✌️✌️✨✨✨♥️✨♥️✨
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