Question

rationalising the denominator 2√5/5-√3​

Answer 1

Step-by-step explanation:

This rationalise will surely help you

Answer 2

Answer:

$\frac{10\sqrt{5} + 2\sqrt{15} }{21}$

Step-by-step explanation:

To rationalize the denominator, multiply and divide the fraction by the conjugate of the denominator.

Here, the denominator is $5 - \sqrt{3}$ and its conjugate is $5 + \sqrt{3}$

Now, let us multiply and divide the given fraction by the conjugate of the denominator, which is $5 + \sqrt{3}$. We get

$\frac{2\sqrt{5} }{5 - \sqrt{3} } \times \frac{5 + \sqrt{3} }{5 + \sqrt{3}} = \frac{10\sqrt{5} + 2\sqrt{15} }{25 - 3} = \frac{10\sqrt{5} + 2\sqrt{15} }{21}$