Math, asked by dasranju1975, 11 months ago

rationalising the denominator 7/3-√2​

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Answered by pratikkhavnekar
0

Answer:

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Rationalizing the denominator

7-3√2/7+3√2

Multiply the numerator and denominator by 7-3√2

=(7-3√2)/(7+3√2)×(7-3√2)/(7-3√2)

write the repeated multiplication in exponential form.

(7-3√2)²/49-9×2

using(a-b)²=a²-2ab+b² expand the expressions

49-42√2+18/49-18

Add the numbers.

67-42√2/49-18

=67-42√2/31

Hope it's help you.

Be Brainliest.

Answered by Manulal857
0

Answer:

Hey Buddy here's ur answer

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