Question

Rationalising the denominator.​

Answer 1

3√3+3√5+3√2/7+ 2√15 has to get more rationalized. So, do that in the same process.

Answer 2

$\implies \frac{3}{3 + \sqrt{5} - \sqrt{2} } \times \frac{3 (3 - \sqrt{5} + \sqrt{2}) }{ 3 - \sqrt{5} + \sqrt{2} }$

$\implies \frac{ 3 (3 - \sqrt{5} + \sqrt{2} )}{ {(3)}^{2} - { (\sqrt{5}) }^{2} + {( \sqrt{2}) }^{2} }$

$\implies \frac{3 (3 - \sqrt{5} + \sqrt{2}) }{9 - 5 + 2}$

$\implies \frac{3 (3 - \sqrt{5} + \sqrt{6}) }{4 + 2}$

$\implies \frac{\cancel3(3 - \sqrt{5} + \sqrt{2} ) }{\cancel6}$

$\implies \frac{3 - \sqrt{5} + \sqrt{2} }{2}$