Math, asked by raziakhaleel198, 10 months ago

rationalising the denominator of 1 upon root 3 - root 2 - 1​

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Answered by jitendrabansal
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Answered by ItSdHrUvSiNgH
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Step-by-step explanation:

 \huge\underline{\underline{\ Answer}} \\  \implies \frac{1}{ \sqrt{3} -  \sqrt{2} - 1  }  \\  \implies  \frac{1}{ \sqrt{3}  -  \sqrt{2} - 1 }  \times  \frac{ \sqrt{3}  +  \sqrt{2} - 1 }{ \sqrt{3} +  \sqrt{2}  - 1 }  \\  \implies \frac{ \sqrt{3} +  \sqrt{2}  - 1 }{3 - 2 + 1}  \\  \implies  \frac{ \sqrt{3}  +  \sqrt{2} - 1 }{2}

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