rationalising the denominator of √8-√5 /√8+√5...plz tell
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Answer:
= 13+2\sqrt{40}40 /3
Step-by-step explanation:
here,\sqrt{8} -\sqrt{5}/\sqrt{8} + \sqrt{5}8−5/8+5
now, \sqrt{8} - \sqrt{5}8−5 /\sqrt{8} + \sqrt{5}8+5 *
so, 8 - \sqrt{40}40 -
here, 13+2\sqrt{40}40 /3
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