Rationalization of root 5 plus root 3 divided by root 5 minus root 3
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Step-by-step explanation:
let us start with taking s where a is positive odd integers we apply the division algorithm with a and b = 4
since 0 <_ r < the possible remainder are 0 ,1,2 and 3
this can be 4q or 4q +1 or 4q +2 or 4q +3
where q is the quotient how ever , since odd a cannot be 4q or 4q + 2
any odd integers is form of 4q + 1 or 4 q + 3
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