Question

Rationalization of the following question

Answer 1

3√2 - 2

Step-by-step explanation:

$\frac{2 \sqrt{3} }{ \sqrt{6} + 2 } \times \frac{ \sqrt{6} - 2}{ \sqrt{6} + 2 } = \frac{2 \sqrt{3}( \sqrt{6} - 2) }{ {( \sqrt{6)} }^{2} - {2}^{2} }$

$\frac{2 \sqrt{18} - 4 \sqrt{3} }{6 - 4}$

$\frac{2( \sqrt{18} - 2)}{2}$

√18-2

√3×3×2 - 2

3√2 - 2

Answer 2

$\frac{2 \sqrt{3} }{ \sqrt{6} + 2 } \\ \\ \frac{2 \sqrt{3} }{ \sqrt{6} + 2} \times \frac{ \sqrt{6} - 2 }{ \sqrt{6} - 2 } \\ \\ \frac{2 \sqrt{3} ( \sqrt{6} - 2) }{ { (\sqrt{6}) }^{2} - {2}^{2} } \\ \\ \frac{2 \sqrt{18} - 4 \sqrt{3} }{6 - 4} \\ \\ \frac{2 \sqrt{9 \times 2} - 4 \sqrt{3} }{2} \\ \\ \frac{2 \times 3 \sqrt{2} - 4 \sqrt{3} }{2} \\ \\ \frac{6 \sqrt{2} - 4 \sqrt{3} }{2}$