Question

rationalization the denominator of root 3+root2 by 5+root 2​

Answer 1

$\sqrt{3} + \sqrt{2 \ } \div 5 + \sqrt{2 } \\ \sqrt{3} + \sqrt{2} \div 5 + \sqrt{2} \times 5 - \sqrt{2} \div 5 - \sqrt{2} \\ ( \sqrt{3} + \sqrt{2} ) \times (5 - \sqrt{2} ) \div {5 }^{2} - { \sqrt{2} }^{2} \\ 5 \sqrt{3} - \sqrt{6} + 5 \sqrt{2} - 2 \div 25 - 2 \\ 5 \sqrt{3} - \sqrt{6} + 5 \sqrt{2} - 2 \div 23$

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