Math, asked by naveen2133, 7 months ago

rationalization the denominotor 5+√3\5-√3​

Answers

Answered by dhamija123
7

We rationalise the denominator of (32−552−3) by multiplying its rationalising factor (32+5) in the numerator and denominator as follows: </p><p></p><p>           </p><p></p><p>32−552−3×32+532+5=(32−5)(32+5)(52−3)(32+5)=</p><p></p><p>(32)2−(5)252(32+5)−3(32+5)=(9×2)−5(5×32×2)+(52×5)−(33×2)−(3×5)</p><p></p><p>=18−5154+510−36−15=13(15×2)+510−36−15=1330+510−36−15    </p><p></p><p>  </p><p></p><p>Hence, 32−552−3=1330+510−36−15</p><p></p><p></p><p>

Answered by prantik60
1

Answer:

(28 + 10✓3)÷22

Step-by-step explanation:

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