Question

rationalize
___1___
√3+√2+ 1
don't give wrong answer or else i will report you

Answer 1

Step-by-step explanation:

1/√3+√2+1 is the given number

the conjugate of 1/√3+√2+1=√3-(√2+1)

Now,multiply the conjugate to the given number both numerator and denominator

=1/√3+√2+1 × √3-(√2+1)/√3-(√2+1)

=√3-(√2+1) / (√3+√2+1)× [√3-(√2+1)]

=√3-(√2+1) / (√3)^2-(√2-1)^2 [since,(a+b)(a-b)=a^2-b^2]

=√3-√2-1 / 3-(2+1-2√2) [ (a-b)^2=a^2+b^2-2ab]

=√3-√2-1 / 3-(3-2√2)

=√3-√2-1 / 3-3+2√2

=√3-√2-1 / 0+ 2√2

=√3-√2-1 / 2√2

Therefore,the rationalised number of √3+√2+1=√3-√2-1 / 2√2

I confidently hope that it is the right answer..

So plzz thank me and follow me yar..

Answer 2

how many times will u post the same question????

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