Math, asked by nonvegfoodin, 1 month ago

rationalize. 1/√3-2​

Answers

Answered by Anonymous
2

 \frac{1}{ \sqrt{3} - 2 }  \times  \frac{ \sqrt{3}  + 2}{ \sqrt{3}  + 2}  \\  \\  \frac{ \sqrt{3}  + 2}{( { \sqrt{3}) }^{2}  - ( {2})^{2} }  \\  \\  \frac{ \sqrt{3}  + 2}{3 - 4}  \\  \\  \frac{ \sqrt{3}  + 2}{ - 1}  \\  \\  -  \sqrt{3 }+ 2

Answered by mihikabhadirge
1

Answer:

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