Question

Rationalize 1/3+√2
$1 \div 3 + \sqrt{2}$
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Answer 1

Answer:

$\frac{1}{3 + \sqrt{2} } \\ \\ \frac{1}{3 + \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ \\ \frac{3 + \sqrt{2} }{9 - 2} \\ \\ \frac{3 + \sqrt{2} }{7}$

Answer 2

Step-by-step explanation:

$\frac{1}{ 3 + \sqrt{2} } \\ rationalising \: the \: denominator \\ \frac{1}{3 + \sqrt{2} } \times \frac{3 - \sqrt{2} }{3 - \sqrt{2} } \\ \frac{3 - \sqrt{2} }{9 - 2} \\ \frac{3 - \sqrt{2} }{7}$