rationalize 1/7+3root 2
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HELLO......FRIEND!!
THE ANSWER IS HERE,
![= > \: \frac{1}{7 + 3 \sqrt{2} } = > \: \frac{1}{7 + 3 \sqrt{2} }](https://tex.z-dn.net/?f=+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B1%7D%7B7+%2B+3+%5Csqrt%7B2%7D+%7D+)
![= > \: \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} } = > \: \frac{1}{7 + 3 \sqrt{2} } \times \frac{7 - 3 \sqrt{2} }{7 - 3 \sqrt{2} }](https://tex.z-dn.net/?f=+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B1%7D%7B7+%2B+3+%5Csqrt%7B2%7D+%7D+%5Ctimes+%5Cfrac%7B7+-+3+%5Csqrt%7B2%7D+%7D%7B7+-+3+%5Csqrt%7B2%7D+%7D+)
![= > \frac{7 - 3 \sqrt{2} }{49 - 18} = > \frac{7 - 3 \sqrt{2} }{49 - 18}](https://tex.z-dn.net/?f=+%3D+%26gt%3B+%5Cfrac%7B7+-+3+%5Csqrt%7B2%7D+%7D%7B49+-+18%7D+)
![= > \: \frac{7 - 3 \sqrt{2} }{31} = > \: \frac{7 - 3 \sqrt{2} }{31}](https://tex.z-dn.net/?f=+%3D+%26gt%3B+%5C%3A+%5Cfrac%7B7+-+3+%5Csqrt%7B2%7D+%7D%7B31%7D+)
:-)Hope if helps u.
THE ANSWER IS HERE,
:-)Hope if helps u.
Ayaankhan1:
how
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hello mate here's ur answer...
this will help you
this will help you
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