Question

Rationalize 1 upon √6+ √5- √3. ??????? Plz send me pic for better understanding

Answer 1

Solution ;-

$= > \frac{1}{ \sqrt{6} + \sqrt{5} - \sqrt{3} } \\ \\ = > \frac{1}{ \sqrt{6} + \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{6} + \sqrt{5} + \sqrt{3} }{ \sqrt{6} + \sqrt{5} + \sqrt{3} } \\ \\ = > \frac{1 \times ( \sqrt{6} + \sqrt{5} + \sqrt{3}) }{( \sqrt{6} + \sqrt{5} ) {}^{2} - ( \sqrt{3} ) {}^{2} } \\ \\ = > \frac{ \sqrt{6} + \sqrt[]{5} + \sqrt{3} }{( \sqrt{6} ) {}^{2} + ( \sqrt{5} ) {}^{2} + 2 \times \sqrt{6} \times \sqrt{5} - 3} \\ \\ = > \frac{ \sqrt{6} + \sqrt{5} + \sqrt{3} }{6 + 5 + 2 \sqrt{30} - 3} \\ \\ = > \frac{ \sqrt{6} + \sqrt{5} + \sqrt{3} }{8 + 2 \sqrt{30} }$

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