Math, asked by ojojashwnishukla, 10 months ago

rationalize 1 upon under root 11 - under root 2​

Answers

Answered by mysticd
1

Answer:

 \red {\frac{1}{\sqrt{11} - \sqrt{2}} }\green {= \frac{ \sqrt{11} + \sqrt{2}}{ 9}}

Step-by-step explanation:

 \frac{1}{\sqrt{11} - \sqrt{2}}

 = \frac{ \sqrt{11} + \sqrt{2}}{(\sqrt{11} - \sqrt{2})(\sqrt{11} + \sqrt{2})}

 = \frac{ \sqrt{11} + \sqrt{2}}{(\sqrt{11})^{2}- (\sqrt{2})^{2})}

 = \frac{ \sqrt{11} + \sqrt{2}}{ 11 - 2 }

 = \frac{ \sqrt{11} + \sqrt{2}}{ 9}

Therefore.,

 \red {\frac{1}{\sqrt{11} - \sqrt{2}} }\green {= \frac{ \sqrt{11} + \sqrt{2}}{ 9}}

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