Math, asked by ashokanagadi, 10 hours ago

rationalize 10/5root3-3root 5

please answer it fast I am giving 10 points

please don't give irrelevant answers
1 irrelevant answer =10 report ​

Answers

Answered by surejamanisha
0

Answer:

your question should be" Rationalizethe denominator of 30/5root3-3root5"

30 /5 \sqrt{3}-3 \sqrt{5} =30/5 \sqrt{3} -3 \sqrt{5} *5 \sqrt{3} +3 \sqrt{5} /5 \sqrt{3} +3 \sqrt{5}30/5

3

−3

5

=30/5

3

−3

5

∗5

3

+3

5

/5

3

+3

5

30(5 \sqrt{3} +3 \sqrt{5} )/ 5^{2} *3- 3^{2} *5 =30(5 \sqrt{3} +3 \sqrt{5} )/75-4530(5

3

+3

5

)/5

2

∗3−3

2

∗5=30(5

3

+3

5

)/75−45

30(5 \sqrt{3} +3 \sqrt{5} ) /30=(5 \sqrt{3} +3 \sqrt{5} )30(5

3

+3

5

)/30=(5

3

+3

5

)

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