Question

rationalize 2+√3 upon 5-√3​

Answer 1

i hope this is help you ....

Answer 2

Answer:

≈ 1.142

Step-by-step explanation:

= $\sf \dfrac{2 + \sqrt{3}}{5 - \sqrt{3}}$

Rationalising the denominator,

= $\sf \dfrac{2 + \sqrt{3}}{5 - \sqrt{3}} \times \dfrac{5 + \sqrt{3}}{5 + \sqrt{3}}$

= $\sf \dfrac{(2 + \sqrt{3}) \times (5 + \sqrt{3})}{(5 - \sqrt{3}) \times {(5 + \sqrt{3})}}$

= $\sf \dfrac{10 + 2 \sqrt{3} + 5 \sqrt{3} + 3}{(5 - \sqrt{3}) \times (5 + \sqrt{3})}$

= $\sf \dfrac{10 + 2 \sqrt{3} + 5 \sqrt{3} + 3}{25-3}$

= $\sf \dfrac{13 + 7 \sqrt{3}}{22}$

= ${\boxed{\sf \approx 1.142}}$