Question

rationalize 2+root3/root3-root2

Answer 1

Multiply numerator and denominator by (√3 +√2) .Then denominator is 3-2=1.
Numerator is (2+√3)(√3+√2)=2√3+2√2+3+√6.
Thats the answer

Answer 2

Hello !!!



2 + ✓3 / ✓3 - ✓2



=> ( 2 + ✓3 ) / ( ✓3 - ✓2 ) × ( ✓3 + ✓2 ) / ( ✓3 + ✓2 )




=> ( 2 + ✓3 ) ( ✓3 + ✓2 ) / ( ✓3 - ✓2 ) ( ✓3 + ✓2 )

=> 2 ( ✓3 + ✓2 ) + ✓3 ( ✓3 + ✓2 ) / (✓3 )² - (✓2 )²



=> 2✓3 + 2✓2 + 3 + ✓6 / 3 - 2



=> ( 2✓3 + 2✓2 + 3 + ✓6 ) / 1


=> ( 3 + 2✓2 + 2✓3 + ✓6 ) [ Answer ]


HOPE IT WILL HELP YOU :-)