Question

rationalize 2 + under root 3 upon 2 minus under root 3​

Answer 1

$\frac{2 + \sqrt{3} }{2 - \sqrt{3} }$

$= > \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} }$

$= > \frac{(2 + \sqrt{3)^{2} } }{4 - 3}$

$= > 4 + 4 \sqrt{3} + 3$

$= > 7 + 4 \sqrt{3}$