Math, asked by CarrabianPirate, 1 year ago

Rationalize 3/✓3+✓5-✓2

Answers

Answered by Anonymous
7
Hey friend !!!!

•°• Here's your answer •°•

que \:  =  \frac{3}{ \sqrt{3} +  \sqrt{5}  -  \sqrt{2}  }  \\  \\ by \:  \: rationalising \:  \: denominator. \\  \\  =  \frac{3}{ \sqrt{3}  +  \sqrt{5}  -  \sqrt{2} }  \times  \frac{ \sqrt{3} -  \sqrt{5}   +  \sqrt{2} }{ \sqrt{3}  -  \sqrt{5}  +  \sqrt{2} }  \\  \\  identity \: \:  used  = (a + b)(a - b) =  {a}^{2}  -  {b}^{2}  \\  \\  \frac{3( \sqrt{3 }  -  \sqrt{5}  +  \sqrt{2}) }{ ({ \sqrt{3}) }^{2}  -   {( \sqrt{5} )}^{2} -  {( \sqrt{2} )}^{2}  }  \\  \\  =  \frac{3 \sqrt{3} - 3 \sqrt{5}   + 3 \sqrt{2} }{3 - 5 - 2}  \\  \\  \frac{3 \sqrt{3} - 3 \sqrt{5}   + 3 \sqrt{2} }{ - 4}

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CarrabianPirate: Hello
CarrabianPirate: Can you solve 3-✓5/3-2√5=a✓5+b
CarrabianPirate: Find the value of a and b
CarrabianPirate: sorry please solve 3-✓5/3+2✓5=a✓5+b
S4MAEL: great job ^_^
S4MAEL: ^_^
Answered by bhavikachopra50
3

Hope you understand

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