Math, asked by atharvraj1479, 9 months ago

rationalize 3 minus root 2 upon 3 + root 2​

Answers

Answered by getsparkling
5

Step-by-step explanation:

3 -  \sqrt[]{2}  \div 3 +  \sqrt{2 }

3-root 2/3+root 2 × 3- root 2 /3-root 2

(3- root 2)^2 / (3)^2-(root 2 )^2

9+2-6root 2 / 9-2

11-6root 2 / 7

11 - 6 \sqrt{2}  \div 7

This is your Answer.

Hope it helps

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