rationalize 3 root 2 / root 6 - root 3
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Answered by
36
Hi friend,
3√2/√6-√3
Rationalising factor is √6+√3
Multiplying and dividing EQUATION 1 with √6+√3
=3√2(√6+√3)/√6-√3(√6+√3)
denominator is of form (a+b)(a-b)=a²-b²
=3√6√2+3√6/(√6)²-(√3)²
=3√12+3√6/3
=√12+√6
HOPE THIS HELPS..........
3√2/√6-√3
Rationalising factor is √6+√3
Multiplying and dividing EQUATION 1 with √6+√3
=3√2(√6+√3)/√6-√3(√6+√3)
denominator is of form (a+b)(a-b)=a²-b²
=3√6√2+3√6/(√6)²-(√3)²
=3√12+3√6/3
=√12+√6
HOPE THIS HELPS..........
Answered by
20
Hello Dear !
_____________________________________________________________
Ratioanlize = 3√2/√6-√3
Mupltiply to both num and den by √6+√3
we get,
3√2X√6+√3/√6-√3X√6+√3
3√12 +3√6/6-3
3(√12+√6)/3
√12+√6
____________________________________________________________
_____________________________________________________________
Ratioanlize = 3√2/√6-√3
Mupltiply to both num and den by √6+√3
we get,
3√2X√6+√3/√6-√3X√6+√3
3√12 +3√6/6-3
3(√12+√6)/3
√12+√6
____________________________________________________________
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