Question

Rationalize and find the value of a and b: 3+√2/ 3-√2= a+b√2​

Answer 1

Answer:

11/7 and (-6/7)

Step-by-step explanation:

3+√2/3-√2. For rationalising i multiply 3+√2 on both numerator and denominator

so

(3+√2)×(3+√2)/(3-√2)(3+√2)

that is

(3+√2)^2/(3^2-(√2)^2)

so

3^2+(√2)^2+2(3)(√2)/(9-2)

9+2-6√2/7

11-6√2/7

11/7 - 6√2/7=a+b√2

so a=11/7

b=-6/7

Answer 2

Answer:

=> ( 3 + root2 ) × ( 3 + root2 ) / ( 3 - root2) × ( 3 + root2 ).

=> ( 3 + root2 )^2 / ( 3^2 - ( root2 )^2).

=> 3^2 + root2^2 + 2 ( 3 ) ( root 2 ) / ( 9 - 2 ).

=> 9 + 2 - 6 root2 / 7.

=> 11 - 6 root2 / 7.

=> 11 / 7 - 6 root2 / 7 = a + b root2.

=> a = 11/7 & b = -6/7.

Step-by-step explanation:

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