Math, asked by kad123, 11 months ago

rationalize denominator 1/√3-√2+1​


helping95: multiply both numerator and denominator by r.f
helping95: RF is root 3 +root 2 -1
kad123: I did need the further steps

Answers

Answered by Needthat
3

 \frac{1}{ \sqrt{3}  -  \sqrt{2} + 1 }  \\  \\  =  \frac{1}{ \sqrt{3}  -  \sqrt{2} + 1 }  \frac{( \sqrt{3} +  \sqrt{2} - 1)  }{( \sqrt{3}  +  \sqrt{2}  - 1)}  \\  \\  \frac{ \sqrt{6}  + 2 -  \sqrt{2} }{4}  \\  \\  =  \frac{ \sqrt{2} ( \sqrt{3} + 1) + 2 }{4}

hope it helps

Answered by saumyasuman05
1

{1/(√3 - (√2 -1)) } *[ { √3 + ( √2 - 1)}]/{( √3 + ( √2 -1)}

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