Question

rationalize denominator 1 by 2 numerator + 3 root​

Answer 1

Answer:

$\green{2-√3}$

Step-by-step explanation:

$\green{Rationalizing}$

$\frac{1}{2 + \sqrt{3} }$

$\frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} }$

using

$\green{(a+b)(a-b)=a^2-b^2}$

$\frac{2 - \sqrt{3} }{(2) {}^{2} - ( \sqrt{3)} {}^{2} }$

$\frac{2 - \sqrt{3} }{4 - 3}$

$\frac{2 - \sqrt{3} }{1}$

$2 - \sqrt{3}$

$\boxed{Hence}$

$\blue{Rationalized}$

Answer 2

Answer:

2-√3

Step-by-step explanation:

1/2+√3

numerator=1

denominator=2+√3

=1/2+√3  *  2-√3/2-√3

=2-√3  /  (2)² - (√3)² [(a+b)(a-b)=a²-b²]

=2-√3  /  4-3

=2-√3