Math, asked by chahatgupta19, 11 months ago

rationalize denominator 1 upon root 5 + root 3 minus root 2

Answers

Answered by sujalronaldo81

1

Answer:

= 1÷√5+√3-√2

=(1÷√5+√3-√2) × (√5+√3+√2÷√5+√3+√2 )

=√5+√3+√2÷5+3-2

=√5+√3+√2÷6

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