Rationalize denominator
√[√2-1/√2+1]
Anonymous:
It is whole root
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{(√2-1)/(√2 +1) }½
={(√2-1)/(√2+1) ×(√2-1)/(√2-1)}½
={(√2-1)²/(√2+1)(√2-1)}½
={(√2-1)²/(√2²-1) }
={(√2-1)²/1}½
={(√2-1)²}½
=(√2-1)
={(√2-1)/(√2+1) ×(√2-1)/(√2-1)}½
={(√2-1)²/(√2+1)(√2-1)}½
={(√2-1)²/(√2²-1) }
={(√2-1)²/1}½
={(√2-1)²}½
=(√2-1)
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