rationalize denominator of following √3-1/√3-1
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Answered by
0
Heya !!!
✓3 - 1 / ✓3 - 1
=> ( ✓3 - 1 ) / ( ✓3 - 1 ) × ( ✓3 + 1 ) / ( ✓3 + 1 )
=> ( ✓3 - 1 ) ( ✓3 + 1 ) / ( ✓3 - 1 ) ( ✓3 + 1 )
=> (✓3)² - (1)² / (✓3)² - (1)²
=> 3 - 1 / 3 - 1
=> 2/2
=> 1
★ HOPE IT WILL HELP YOU ★
✓3 - 1 / ✓3 - 1
=> ( ✓3 - 1 ) / ( ✓3 - 1 ) × ( ✓3 + 1 ) / ( ✓3 + 1 )
=> ( ✓3 - 1 ) ( ✓3 + 1 ) / ( ✓3 - 1 ) ( ✓3 + 1 )
=> (✓3)² - (1)² / (✓3)² - (1)²
=> 3 - 1 / 3 - 1
=> 2/2
=> 1
★ HOPE IT WILL HELP YOU ★
Answered by
0
Here is your answer
root 3 - 1 ÷ root 3 - 1
root 3 - 1 / root 3 - 1 × root 3 + 1 / root 3 - 1
( root 3 )^2 - ( 1 )^2 ÷ ( root 3 )^2 - (1)^2
2÷2 = 1
Hope it helps you ^_^
root 3 - 1 ÷ root 3 - 1
root 3 - 1 / root 3 - 1 × root 3 + 1 / root 3 - 1
( root 3 )^2 - ( 1 )^2 ÷ ( root 3 )^2 - (1)^2
2÷2 = 1
Hope it helps you ^_^
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