Question

rationalize in the form of A and B​

Answer 1

Step-by-step explanation:

$\frac{ \sqrt{3} - 1}{ \sqrt{ 3} + 1 } \\ = \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1 } \times \frac{ \sqrt{3} - 1 }{ \sqrt{3} - 1} \\ = \frac{ {( \sqrt{3} - 1) }^{2} }{( \sqrt{3} + 1)( \sqrt{3} - 1) } \\ = \frac{3 - 2 \sqrt{3} + 1 }{ {( \sqrt{3} )}^{2} - 1 } \\ = \frac{4 - 2 \sqrt{3} }{3 - 1} \\ = \frac{4 - 2 \sqrt{3} }{2} \\ = \frac{2(2 - \sqrt{3} )}{2} \\ = 2 - \sqrt{3}$

Therefore, a=2 , b =-1