Math, asked by manupratapsingh, 10 months ago

rationalize root 2 minus 3 root 5 upon 2 root 2 + 1 root 5

Answers

Answered by hdewangan
0

 \frac{ \sqrt{2} - 3 \sqrt{5}  }{2 \sqrt{2}  + 1 \sqrt{5} }  \\  \\  =  \frac{ \sqrt{2}  - 3 \sqrt{5} }{2 \sqrt{2}  + 1 \sqrt{5} }  \times  \frac{2 \sqrt{2}  - 1 \sqrt{5} }{2 \sqrt{2} - 1 \sqrt{5}  }  \\  \\  =  \frac{ \sqrt{2}(2 \sqrt{2} - 1 \sqrt{5}  ) - 3 \sqrt{5}(2 \sqrt{2 } - 1 \sqrt{5)}    }{ {(2 \sqrt{2)}  }^{2} -  {(1 \sqrt{5)} }^{2}  }  \\  \\  =  \frac{4 - 1 \sqrt{10} - 6 \sqrt{10}   + 15}{8 - 5}  \\  \\  =  \frac{19 - 7 \sqrt{10} }{3}

Hope it helps.

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