Question

rationalize root 3 + root 5 upon root 2 minus 1​

Answer 1

hope it helps..........

Answer 2

Solution:

Given (√3+√5)/(√2-1)

Rationalising the denominator,

we get

= [(√3+√5)(√2+1)]/[(√2-1)((√2+1)]

= [√6+√3+√10+√5][(√2)²-1²]

/* (a+b)(a-b) = a²+b² */

= (√3+√5+√6+√10)/(2-1)

= (√3+√5+√6+√10)

••••