Question

Rationalize
te the denominator 6/9√3​

Answer 1

Answer:

$\frac{6}{9 \sqrt{3} } = \frac{2}{3 \sqrt{3} } \\ \frac{2}{3 \sqrt{3} } \times \frac{3 \sqrt{3} }{3 \sqrt{3} } \\ = \frac{6 \sqrt{3} }{9 \times 3} \\ = \frac{6 \sqrt{3} }{27} \\ = \frac{2 \sqrt{3} }{9}$

I hope it will help you

Answer 2

Answer:

$\frac{6}{9 \sqrt{3} } \\ = \frac{6}{9 \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ = \frac{6 \sqrt{3} }{9 (\sqrt{3})^{2} } \\ = \frac{2 \sqrt{3} }{9}$

.......hope......it.......helps......u