Question

rationalize
$( \sqrt{2} + \sqrt{3} ) \div (3 \sqrt{2} - 2 \sqrt{3} )$
​

Answer 1

$\orange{\boxed{\green{\underline{\red{\mathrm{Solution:-}}}}}}$

$\frac{2+ \sqrt{3}}{3 \sqrt{2}-2 \sqrt{3}}$

Multiply by 3√2+2√3

*The denominator then rationalizes*

→(3√2-2√3)×(3√2+2√3)

→(3√2)²-(2√3)²

→18-12

→6

→Denominator becomes 6

*As we multiplied 3√2+2√3 in denominator,we have to multiply it in numerator too*

→(2√3)×(3√2+2√3)

*this can be left here as we have to Rationalize the Denominator*

→$\frac{2 \sqrt{3}×3 \sqrt{2}+2 \sqrt{3}}{6}$

$\rule{200}{1}$