Question

rationalize the deniminater in the following. 1/√5 + √2​

Answer 1

HEY MATE,LET ME HELP YOU WITH IT......:D

QUERY:1/√5+√2

TASK:TO RATIONALISE DENOMINATOR

SOLUTION:

FIRSTLY,WRITE THE FRACTION IN THE SAME FORM,

1/√5+√2

NOW,WE KNOW,WHENEVER WE HAVE TO RATIONALISE ANY FRACTION WITH DOUBLE COMPONENT DENOMINATOR,WE JUST MULTIPLY THE WHOLE FRACTION WITH THE SAME DENOMINATOR OF THE FRACTION,BUT WITH REVERSED SIGNS{I.E.+ BECOMES (-) ;& -BECOMES (+)}

∴HERE,DENOMINATOR=√5+√2

∴RATIONALISING FRACTION,(1/√5+√2)*√5-√2

AFTER MULTIPLICATION,WE GET √5-√2/[(√5-√2)(√5+√2)]

SIMPLIFYING FURTHER,WE GET,√5-√2/$\sqrt{5}^{2} + \sqrt{2}^{2}$

[USING $(a+b)(a-b)=a^2-b^2$]

NOW,MAKING IT MORE SIMPLIER,WE GET,

√5-√2/5-2     [ ∵√A^2=A]

⇒√5-√2/3

SO MATE,YOUR QUERY HAS BEEN SOLVED...HENCE YOUR ANSWER IS √5-√2/3.

PLEASE CONSIDER MARKING MY ANSWER AS BRAINLIEST....:D