Question

Rationalize the denomina
in the
follwoing

1×√5+√2​

Answer 1

Answer:

it is already rationalized

Step-by-step explanation:

There is no denominator in your question

Answer 2

$\bf\therefore\red{NOTE:-\: GIVEN\: QUESTION \:IS\: WRONG.}$

$\large\underline\bold\purple{CORRECT \:QUESTION,}$

$\bf\dashrightarrow \dfrac{1}{\sqrt{5}+ \sqrt{2}}$

ANSWER✔

$\large\underline\bold{GIVEN,}$

$\bf\dashrightarrow \dfrac{1}{\sqrt{5}+ \sqrt{2}}$

$\large\underline\bold{TO,RATIONALISE\:THE\:DENOMINATOR}$

✯IDENTITY IN USE,

$\large{\boxed{\bf{ \star\:\: (a+b)(a-b)=a^2-b^2 \:\: \star}}}$

$\large\underline\bold{SOLUTION,}$

$\sf\therefore \dfrac{1}{\sqrt{5}+ \sqrt{2}}$

$\sf\therefore\blue{multiplying \:both \:numerator\: and \:denominator\: by \:\sqrt{5}- \sqrt{2}}$

$\sf\implies \dfrac{1}{\sqrt{5}+ \sqrt{2}} \times \dfrac{\sqrt{5}- \sqrt{2}}{\sqrt{5}- \sqrt{2}}$

$\sf\implies \dfrac{\sqrt{5}- \sqrt{2}}{(\sqrt({5})^2- (\sqrt{2})^2}\:---\boxed{using\:given\: identity}$

$\sf\implies \dfrac{\sqrt{5}- \sqrt{2}}{5-3}$

$\sf\implies \dfrac{\sqrt{5}- \sqrt{2}}{2}$

$\large{\boxed{\bf{ \star\:\: \dfrac{\sqrt{5}- \sqrt{2}}{2} \:\: \star}}}$

$\large\underline\bold{THE\:RATIONALISED\: DENOMINATOR\:IS\:\dfrac{\sqrt{5}- \sqrt{2}}{2}}$

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