Question

Rationalize the denominater
3+√3
3-√3​

Answer 1

Answer:

$\frac{3 + \sqrt{3} }{3 - \sqrt{3} } = \frac{ {(3 + \sqrt{3} )}^{2} }{(3 + \sqrt{3})(3 - \sqrt{3} ) } \\ = \frac{(9 + 3 + 6 \sqrt{3}) }{(9 - 3)} \\ = \frac{12 + 6 \sqrt{3} }{6} \\ = (2 + \sqrt{3} ) \\ \boxed{(2 + \sqrt{3}) \: is \: the \: right \: answer. }$

hope this helps.