rationalize the denominater of 4√3÷√(5+√2)
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=4√3/√5+2
=4√3(√5-2)/(√5+2)(√5-2)
=(4√15-8)/(√5)^2-(2)^2
=4(√15-2)/5-4
=4(√15-2)/1
=4(√15-2)...
=4√3(√5-2)/(√5+2)(√5-2)
=(4√15-8)/(√5)^2-(2)^2
=4(√15-2)/5-4
=4(√15-2)/1
=4(√15-2)...
avnigupta33:
its wrong
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