Question

rationalize the denomination 1/3-√2​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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$\frac{1}{3 - \sqrt{2} } = \frac{1}{3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} } \\ = \frac{3 + \sqrt{2} }{(3 + \sqrt{2)(3 - \sqrt{2} } } = \frac{3 + \sqrt{2} }{ {3}^{2} - \sqrt{ {2}^{2} } } = \frac{3 + \sqrt{2} }{9 - 2} = \frac{3 + \sqrt{2} }{7} or \frac{1}{7} (3 + \sqrt{2)}$